4x^2-15x-91=0

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Solution for 4x^2-15x-91=0 equation:



4x^2-15x-91=0
a = 4; b = -15; c = -91;
Δ = b2-4ac
Δ = -152-4·4·(-91)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-41}{2*4}=\frac{-26}{8} =-3+1/4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+41}{2*4}=\frac{56}{8} =7 $

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